Given lengths R and r with R > 2r. Construct a triangle with side lengths in arithmetic progression and R and r its circumradius and inradius respectively.

(In reply to solution by Daniel)

Your problem was this step

(b^2-k^2)/(6r)>2r

b^2-k^2<12r^2

It should be

b^2-k^2>12r^2

Posted by Bractals on 2007-01-30 15:13:14