Consider the parallelogram PQRS with PS parallel to QR and PQ parallel to SR. The bisector of the angle PQR intersects PS at T.

Determine PQ, given that TS = 5, QT = 6 and RT = 6.

Angle PQT = angle RQT = angle PTQ = angle TRQ -->

Triangle QPT is similar to triangle QTR

Also let x = PQ = PT. Since QR = x+5, x/6 = 6/(x+5) -->

PQ = x = 4.

Posted by Dennis on 2007-05-01 10:14:00