Determine all possible positive whole numbers t such that t is equal to the sum of the squares of its four smallest positive divisors including 1.

For example, 1, 2, 4 and 5 are the four smallest positive divisors of 40.
But, 1² + 2² + 4²+ 5² = 46. So, t = 40 is NOT a valid solution.

(In reply to Sum thoughts by Leming)

erroneous comment deleted

Edited on May 3, 2007, 4:05 pm

Posted by Charlie on 2007-05-03 16:04:11