perplexus.info :: Geometry : A point in a square

A point in a square (Posted on 2004-03-17)

Given a square ABCD, let P be such that AP=1, BP=2 and CP=3.

* What is the length of DP?
* What is the angle APB?

See The Solution Submitted by Federico Kereki

Rating: 3.1250 (8 votes)

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answer

Comment 7 of 7 |

Applying Pythagoras, it's easy to prove that AP²+CP²= BP²+DP².

then DP². = 1^2+3^2-2^2 =6, so that: DP = v6 =

Angle APB = 45 degrees

Edited on June 19, 2023, 2:52 am

Posted by K Sengupta on 2007-05-12 13:41:24

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