Seven of our members at Perplexus decided to try their luck on the UK Lottery. They each chose six different numbers from 1 to 49. (None of them chose the same number.)

If all six numbers were drawn, they would win millions; if five of their numbers, plus the bonus came up, they would win a few hundred thousand.

Brianjn chose multiples of three.
Dej Mar's greatest number was ten.
Federico chose primes totalling 150.
Assaf and Vernon each chose six consecutive numbers, Assaf's being higher in value.
Penny chose multiples of seven.
Charlie chose square numbers.

Would you believe these unlucky punters failed to choose a single correct number (not even the bonus)?

If the bonus number was 1, which six numbers came up on the lottery?

(In reply to some selections (spoilers) by jduval)

Ok.  Fed Since he has two in the set (29,31,37,41, 43, and 48) and A and V have 4 of that set this leaves Fed with 37 and 41 and since he has 4 in the set (11,13,17,19,23) the 41 has to match up with the 19 to make the 10 multiple and this eliminates the 11 since there is not a x9 to make a second multiple of 10)

Leaving Federico choosing (13,17,19,23,37,41).

AND FINALLY -

leaving 11,20,22,26,38,40 to be chosen by me for several million dollars. Don't I wish. Of course I would split all my winnings with Assaf, Vernon, Charlie, Penny, Federico, BrianJn, DejMar for so diligently helping me pick my numbers and of course Josie for creating such a wonderful problem (only if it were a method to ensure we all win millions).

Edited on May 30, 2007, 2:00 pm

Posted by jduval on 2007-05-30 13:53:11