You are in a free-for-all shootout involving three people, and by some rotten luck, you are the worst shooter of the group. You, shooter
A, hit your target 33% of the time.
The other two,
B and
C, have 50% and 100% accuracy respectively.
At least you get to shoot first, with B going after you, and C going last. Everyone takes turns shooting until all but one are dead.
Who will you fire at in the first round to maximize your odds of survival?
So if you only shoot with 33% accuracy and you intentionally miss do you have a 66% chance of hitting one of them. I would say those would be better odds. i.e. 33% chance of missing no one=66% chance of hitting someone. LOL.
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Posted by jduval
on 2007-06-17 21:10:45 |