Is it ever the case that 2
m+3
m is a
perfect power, whenever m is a positive prime number?
All perfect even powers are also squares.
All squares = 0 or 1 mod 4.
For m > 1, 2^m + 3^m = 1 or -1 mod 4, according to whether m is even or odd.
So m is even, say m=2n.
Then 2^m + 3^m = 2^2n + 3^2n = 4^n + 9^n = (-1)^n + (-1)^n mod 5 = 2 or -2 mod 5.
But all squares can only = 0, 1, or -1 mod 5.
So 2^m + 3^m can never be a perfect square, and thus not a perfect even power.
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Posted by xdog
on 2007-06-28 21:00:43 |