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Sum Three Factorials, Get Exponent (Posted on 2007-07-03)

Determine all possible quadruplets (p, q, r, s) of positive integers with p< = q< = r satisfying the equation p! + q! + r! = 2^s.

See The Solution Submitted by K Sengupta

Rating: 4.0000 (1 votes)

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Just for starters

| Comment 1 of 8

Obviously 1+1+6=8, so (1,1,3,3) is an answer, but I couldn't find another one...

Edited on July 3, 2007, 10:27 am

Posted by Federico Kereki on 2007-07-03 10:26:39

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