Determine all possible quadruplets (p, q, r, s) of positive integers with p< = q< = r satisfying the equation p! + q! + r! = 2^s.

These quadruplets satisfy the equation:

{(1,1,2,2),(1,1,3,3),(2,3,4,5),(2,3,5,7)}

These are the only solutions I could find for s<100.  We know that p,q, & s cannot be equivalent since the sum of their factorials would be divisible by 3.

Posted by hoodat on 2007-07-03 14:21:40