Take one 1, two 2s, three 3s, four 4s, five 5s, six 6s, seven 7s, and eight 8s and place them in a 6-by-6 grid, one digit per square, such that each row, column, and major diagonal sums to 34.

One of the arrangements is as follows:

8..4..4..4..6..8
8..8..3..7..3..5
6..4..7..8..7..2
7..5..6..1..8..7
2..6..6..8..5..7
3..7..8..6..5..5

Posted by K Sengupta on 2007-08-23 14:45:05