The number N is obtained by rearranging the digits of a positive decimal whole number M.

Can M+N be equal to 99.....9, where the digit 9 is repeated precisely 2007 times?

(In reply to solution by bubu)

bubu: Agree that with my solution the number of 4s in the first number equal the number of 5s in the second. 

Also agree that the number of 4s in the first number equal the number of 4s in the second. And the number of 5s in the first number equal the number of 5s in the second.

The only problem with my solution is whether it is limited to integers or limited to real numbers.

Posted by Leming on 2007-10-16 16:45:12