Let I be the incenter of ABC. AI, BI, CI intersect the circumcircle of ABC again at A', B', C' respectively. Show that the area of A'B'C' >= the area of ABC
Strange we've had no takers for this one. Has it looked too similar to those of K Sengupta that people have thought that they had already visited it?
That said, I currently don't have time at the moment but intend to come back, unless some offers in the meantime.
My diagram (very rough sketch) looks like a hexagonal star. On the basis of the diagram I'd offer a surmise but wouldn't be appropriate, we need proof.
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Posted by brianjn
on 2007-11-06 02:49:17 |