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Quadrilateral With A Difference (Posted on 2007-11-08) Difficulty: 3 of 5
EFGH is a convex quadrilateral having diagonals EG and FH. It is known that EF = GH, while EH/FG = √3 + 1 and Angle GHE - Angle HEF = 30o.

Determine the value of (Angle EFG - Angle FGH).

See The Solution Submitted by K Sengupta    
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Solution answer (spoiler) but no proof | Comment 1 of 3
Working with Geometer's Sketchpad indicates the answer should be 90°
  Posted by Charlie on 2007-11-08 12:45:05
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