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Quadrilateral With A Difference (
Posted on 2007-11-08
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EFGH is a convex quadrilateral having diagonals EG and FH. It is known that EF = GH, while EH/FG = √3 + 1 and Angle GHE - Angle HEF = 30
o
.
Determine the value of (Angle EFG - Angle FGH).
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Submitted by
K Sengupta
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answer (spoiler) but no proof
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Working with Geometer's Sketchpad indicates the answer should be 90°
Posted by
Charlie
on 2007-11-08 12:45:05
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