Each of the sides PQ, QR, RS, ST, TU, UV and VP of a regular
heptagon PQRSTUV have length 2. The respective lengths of two of the diagonals PR and PS of the heptagon are denoted by X and Y.
Determine 1/X + 1/Y.
(In reply to
Solution by Brian Smith)
I have to agree with Steve. Kudos. I suspected there might be something related to the quadrilateral that might simplify and find the more exact solution. I shall try to remember Ptolemy's Theorem for future reference.
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Posted by Dej Mar
on 2007-11-18 01:21:23 |