The six sides of a
cyclic hexagon PQRSTU are PQ, QR, RS, ST, TU and UP. It is known that PQ= RS= TU and the diagonals PS, QT and RU meet at the point V. The lines PS and RT intersect at the point W.
Determine the ratio RW/WT, given that PR = 3*RT.
. . . . . . .
. .
. .
. .
. .
. .
.Q R .
. .
. .
. .
. .
. .
. .
. V WS
P T
. .
. .
. .
. .
. .
. .
. .
. .U
. .
. .
. .
. . . . . . .
Unfortunately the reader must visualise the lineal connections.
It's easy to find the ratio if you know that PU = QR. Playing around with Geometer's Sketchpad, the givens of the problem seem to force PU to equal QR. I'm still trying to prove it.
|
Posted by Bractals
on 2007-12-09 03:45:26 |