The six sides of a
cyclic hexagon PQRSTU are PQ, QR, RS, ST, TU and UP. It is known that PQ= RS= TU and the diagonals PS, QT and RU meet at the point V. The lines PS and RT intersect at the point W.
Determine the ratio RW/WT, given that PR = 3*RT.
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.Q R .
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. V WS
P T
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. .U
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Unfortunately the reader must visualise the lineal connections.
(In reply to
More Thoughts by Brian Smith)
Without a Geometer's Sketchpad it is difficult to find where the diagonals PS, QT and RU might meet at point V and where PR = 3*RT, and I suspect it might be easier to algebraically and trigonometrically solve this. Nonetheless, using Paint as my "Geometer's Sketchpad" I can give what I believe might be an approximate ratio -- 8:1. Unfortunately I can not yet prove this nor be certain how close to accurate my guess is.
Edited on December 11, 2007, 3:53 am
|
Posted by Dej Mar
on 2007-12-10 06:43:44 |