Using “Only Four” ZEROS (0) and any Mathematical Operations/Symbols [for example: 'e', 'pi',.... etc., if necessary], obtain the number 24.
(e^(i*pi)+e^(i*pi))*(e^(i*pi)+e^(i*pi))*(e^(i*pi)+e^(i*pi))*(e^(i*pi)+e^(i*pi)+e^(i*pi))+0+0+0+0 which translates to (-2)*(-2)*(-2)*(-3)+0+0+0+0
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Posted by Charlie
on 2003-04-09 04:38:36 |