A string of
2001 digits begins with a "
6". Any number formed by two consecutive digits is divisible by either
17 or
23.
What is the last digit in this sequence?
What if the sequence had 2002 digits?
(i) The required last digt of the sequence is 6.
(ii) If the sequence had 2002 digits, then the last digit of the sequence would have been either 9 or 8.
Edited on December 23, 2007, 12:00 pm