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Consecutive Near Palindromes (Posted on 2008-02-13) Difficulty: 3 of 5
Find a set of four consecutive six digit numbers which satisfies the following:
  • The last four digits of the first (smallest) number form a palindrome.
  • The last five digits of the second number form a palindrome.
  • The second through fifth digits of the third number form a palindrome.
  • The fourth (largest) number is a palindrome.

See The Solution Submitted by Brian Smith    
Rating: 3.3333 (3 votes)

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Solution Solution | Comment 2 of 9 |
The set of four consecutive six digit numbers is
(198888, 198889, 198890, 198891).
  • The last four digits of 198888 is 8888, which is a palindrome.
  • The last five digits of of 198889 is 98889, which is a palindrome.
  • The second through fifth digits of 198890 is 9889, which is a palindrome.
  • 198891 is a palindrome.

  Posted by Dej Mar on 2008-02-13 12:08:57
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