In the problem Calendar cubes you figured out the maximum amount of days you could fit on two cubes by putting numbers on both cubes and using the faces of the cubes to combine and make more numbers.
In Calendar cubes pt 2 You figured out how many months you could fit on two cubes.
Now in calendar cubes pt 3 you must figure out how many days of the year you can fit on two cubes. E.G one cube says mar(for march) and another says 5. so you could make the date march 5 and that would count as one date.

To represent months you may use
a) the first letter of that month
b) the first and second letter of that month
c) the first three letters of that months. So for january you could use either j, ja or jan to represent that month.
Also no two letters or letter combinations can represent the same month. So j cannot stand for june and july, but you can have j stand for june and ju stand for july. Also note that one month symbol (lets say au for august) can be on 1 face of 1 cube.

Ok i know this problem only got two votes but its at 1? is there any justification behind this reasoning? just to start off you guys (I'm not angry at those who didn't vote)did not find the maximum number of combinations, secondly there is simply one genious concept you have to come across. I honestly don't think this problem should be a 1 and if you think differently vote on it.

Posted by Alan on 2003-04-10 10:38:22