We shall assume no leading zeroes, where, otherwise,
00 + 0 = 00 could be a solution.
We shall also assume the equation was not meant to be interpreted as M*A + A = A*M, where A = 0 and M can be any digit.
Given the radix, B, of the two digit number AM, such that the radix is greater than 2, the solution to the two digits A and M are where A = (B - 2) and M = (B - 1). For base 10 (the normal default when no radix is given) the solution would be:
A = (10 - 2) =
8 and
M = (10 - 1) =
9.
89
10 + 9
10 = 98
10;
EF
16 + F
16 = FE
16;
45
6 + 5
6 = 54
6;
etc.
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Posted by Dej Mar
on 2008-02-29 12:54:24 |
Solution
