Here is a cool sequence.
1,10,101,1020,10301,______,_______...
What numbers go in the two blanks?
(In reply to
Answer by K Sengupta)
Let the pth term of the sequence be S(p).
Then, the terms are given by the recursion relation:
S(p) = S(p-2) + 10*S(p-1)
Accordingly, we observe that:
S(3) = 1 + 10*10 = 101
S(4) = 10 + 10*101 = 1020
S(5) = 101 + 10*1020 = 10301
S(6) = 1020 + 10*10301 = 104030
S(7) = 10301 + 10*104030 = 1050601
Consequently, the missing 6th and 7th terms are respectively 104030 and 1050601
Puzzle Solution With Explanation
