perplexus.info :: Shapes : Shape Invariant

Shape Invariant (Posted on 2008-03-31)

A (not necessarily regular) solid has F faces, each one of which has A sides. It also has V vertices, each of which is the meeting place of B faces.

Show that AF = BV

See The Solution Submitted by FrankM

Rating: 2.5000 (2 votes)

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Tautology

Comment 2 of 2 |

Both sides of the equation count the number of face vertices.

Posted by Bractals on 2008-03-31 14:05:25

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