What is the center of gravity of the perimeter of a triangle (as when a piece of wire is bent into triangular form)?
(In reply to
solution by Dej Mar)
Consider vertices (-.01,0), (.01,0), (0,6). The centroid formula gives (0,2), but the small base has hardly any weight, and the CG should be quite near (0,3), near the middle of the long sides.
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Posted by Charlie
on 2008-05-19 12:14:45 |
re: solution
