You can use the digits 1,2,and 3 once only and any mathematical symbols you are aware of, but no symbol is to be used more than once. The challenge is to see if you can make the smallest positive number.
Special rules: You cannot use Euler's number or pi or infinity.
Special thanks to: Rhonda Wendel for Make the most of these digits and for the problem text which was slightly altered.
The smallest positive number that I can suggest using the digits 1,2 and 3 is :
[(21)^(-3)]!
Which is equal to one divided by the cube of 21 and then the factorila of that result, so that the numerator is equal to 1 and the denominator is equal to (9261)!, thus giving us the result :
[1/(9261)!]
which is the smaallest number that I could think of till now, using the digits 1,2 and 3 only, i.e., [(21)^(-3)]!
Let's see if anybody else has any other number in his/her mond.
This is my Guess........
