Determine all 6 digit perfect squares such that the first three digits form a perfect square as do the last three.
The square formed by the first three digits may not have leading zeroes.
(In reply to
re: Solution - an "imperfect" square by brianjn)
An imperfect (square) power is a number whose (square) root cannot be expressed soley as an integer.
An example of an imperfect square (also an imperfect power, in general) is the number 5:
51/2 = 2.23606797749978969640917366873~
51/3 = 1.70997594667669698935310887254~
51/4 = 1.49534878122122054191189899414~
...
8 is an imperfect square, yet it is a perfect cube:
81/2 = 2.82842712474619009760337744841~
81/3 = 2
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Posted by Dej Mar
on 2008-08-26 23:41:21 |