I bought a new calculator at the Dollar Store and, sure enough, it’s defective. After some trial and error with it, I discovered that each digit in the display contained the same two pairs of elements (out of the seven elements labeled A to G below) that were somehow ‘cross-wired’. That is, if one element was called upon to illuminate, its partner would illuminate instead. If both were supposed to illuminate, neither would! For example, if A/D and B/F were the faulty pairs, the number 3 would simply display as F/G/C, as illustrated below.
Based on the illuminated elements for each digit given below, find the faulty pairs to then solve the following 3-digit by 2-digit multiplication:
| | C/D | F/B/G/E/C | G/E/C |
| X | | F/G/C/D | F/G/E/C/D |
| F/E/C/D | F/G/C/D | F/G/E/C/D | F/E/C/D |
(In reply to
re: problems with computer program by brianjn)
Um? Should the line:
IF tothad > maxhad THEN maxhad = tothad: numbmax = 1
be written as:
IF tothad > maxhad THEN
maxhad = tothad
numbmax = 1
ENDIF ?
Both versions do the same thing. When a THEN is followed by further statements on the same line, the conditional nature ends (as if by an ENDIF) at the end of the line. When the THEN is the last thing on the line, the conditional nature ends only with the ENDIF.
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Posted by Charlie
on 2009-02-19 02:49:06 |
re(2): problems with computer program
