Solve this alphametic, where ten and nine are respectively numbers in base 10 and base 9 notation. Each of the small letters in bold represents a different digit, and none of the numbers contains any leading zero.

(ten)₁₀ - (nine)₉ = 1

(In reply to computer solution by Daniel)

Since N * 9^3 gives a 4-digit decimal number when N>2, N=1.

Substituting, 100T = 0 mod 9, so T=9.

Then 9I - E = 18, so E=0 and I=2.

Posted by xdog on 2009-04-23 13:47:31