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Draw the following set of convex polygons with vertices in ascending and consecutive alphabetical order:
triangle, square, pentagon, hexagon, heptagon and octagon.
Each vertex sequence begins with an
A with subsequent (and all) vertices being 3 squares apart as defined by a chess knight's "L" shaped move or the queen's diagonal or orthogonal move.
No polygon is to have a common vertex with another. Should this occur then one or the other is not part of the solution.
Interesting puzzle! I worked backwards, beginning with the octagon and then moving back until I found the triangle.
My vertices:
triangle - D3, G3, G6
square - F1, I4, F7, C4
pentagon - B4, B7, E7, H4, E1
hexagon - G8, D8, A5, D2, G2, J5
heptagon - E6, G7, J4, I2, G1, E2, D4
octagon - F6, D7, B6, A4, B2, D1, F2, G4
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Posted by Jyqm
on 2009-04-24 17:05:39 |
solution
