Solve this alphametic, where each of the capital letters in bold denotes a different decimal digit from 0 to 9. None of the numbers can contain any leading zero.
3√(HOW)+ 3√(AND) = 3√(WHEN)
No smoke or computer screens needed for this check..
192^(1/3) + 375^(1/3)
= (64 x 3)^(1/3) + (125 x 3)^(1/3)
= 64^(1/3) x 3^(1/3) + 125^(1/3) x 3^(1/3)
= 4 x 3^(1/3) + 5 x 3^(1/3)
= 9 x 3^(1/3)
= 729^(1/3) x 3^(1/3)
= (729 x 3)^(1/3)
= 2187^(1/3)
Edited on July 31, 2009, 9:44 pm
Edited on July 31, 2009, 9:50 pm
|
Posted by Harry
on 2009-07-31 21:40:22 |