You and a friend play a game in which there are an odd number of rocks. You can take 1, 2 or 3 rocks on your turn (alternating turns with your opponent); when all rocks have been taken, the person who has taken an odd number of rocks is the winner.
If you are the first to go, what strategy should you use in order to have the best chance of winning?
(In reply to
Strategy by Rich)
...5 left - you take 1, the opponent is left with 4, and after him taking any amount, we are left with 1,2,3 again - and we know how to win.
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*the opponent will then take 3 - and you lose
re: wrong Strategy
