Let P be a point in the interior of an equilateral triangle.
Three line segments connect P with the vertices of the
triangle and three line segments connect P perpendicularly
to the sides of the triangle.
These six line segments divide the triangle into six smaller
triangles that surround P.
If u, v, w, x, y, and z denote the areas of the triangles
around P in that order, then prove that
u + w + y = v + x + z.
(In reply to
re(2): Easy when you know how by broll)
Hello again Broll
I'm happy about the triangle having unit sides, but I'm still wondering why
i(1-b)+k(1-d)+m(1-f) becomes i-ai+k-ck+m-em on the next line.
Am I missing something?
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Posted by Harry
on 2010-04-18 21:45:01 |
re(3): Easy when you know how
