All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Back to the Wall (Posted on 2010-04-28) Difficulty: 3 of 5


No! Not a firing squad nor the need for a continuous line to cross all line segments just once!

To each vertex labeled A to L apply a different value from 1 to 12. Let V, W, X, Y and Z be the sums of their respective surrounding vertices.

Provide at least one example where V=W=X=Y=Z, or offer a reason why this, like the continuous line, is impossible.

See The Solution Submitted by brianjn    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
If rectangle sums only of counters... | Comment 6 of 17 |

If one considers "vertex" as limiting the sums of each rectangle to the corners (i.e. leaving out F, G, and H from the sums of Y, W, and Z respectively) there will be a set of sums for each method.  If, for each method of calculating, one lists the numbers which occur as sums, there is an interesting difference in these lists.  For one the possibilities are all consecutive; for the other there is a gap in the possible sums.  Can you identify?

 


  Posted by ed bottemiller on 2010-04-29 16:40:14
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information