In the problem
Calendar cubes you figured out the maximum amount of days you could fit on two cubes by putting numbers on both cubes and using the faces of the cubes to combine and make more numbers.
In
Calendar cubes pt 2 You figured out how many months you could fit on two cubes.
Now in calendar cubes pt 3 you must figure out how many days of the year you can fit on two cubes. E.G one cube says mar(for march) and another says 5. so you could make the date march 5 and that would count as one date.
To represent months you may use
a) the first letter of that month
b) the first and second letter of that month
c) the first three letters of that months. So for january you could use either j, ja or jan to represent that month.
Also no two letters or letter combinations can represent the same month. So j cannot stand for june and july, but you can have j stand for june and ju stand for july. Also note that one month symbol (lets say au for august) can be on 1 face of 1 cube.
The primary month cube could have the faces J, A, M, A, S and AU. The style of the A's would be with a rounded top and short legs so when tilted can be used as a D with serifs. The M would be stylized, so when tilted may represent the number 3. The S would also be stylized so may represent the number 5. The J could be stylized, so that when tilted it may represent the number 4. For January and March, the cube would be turned so that two faces of the cube would be shown.
+---+---+ +---+---+ +-----+ +-----+
| | | | | | | | | |
| J | A | | M | A | | A | | M |
| | | | | | | | | |
+-------+ +-------+ +-----+ +-----+
January March April May
+-----+ +-----+ +-----+ +-----+
| | | | | | | |
| J | | S | | AU | | D |
| | | | | | | |
+-----+ +-----+ +-----+ +-----+
June September August December
The day cube could have the faces 1, 2, 0, 9, 3 and 5. The 0, 1 and 2 would be stylized so as to have 180-degree rotational symmetry, this allows the numbers 10, 12, 16, 20, 21, and 30 to be formed with turning the cube to show two faces. When rotated 90-degrees, the 2 could also represent a stylized letter N (November). The 6 when rotated 180-degrees would also be a 9. The 3 would be stylized in such a way as to also represent, when turned, an M (March). The zero would be stylized so as to also be usable as the letter O (October). And the 5 would be stylized to also represent an S (September).
+-----+ +-----+ +-----+ +-----+ +-----+ +-----+
| | | | | | | | | | | |
| 1 | | 2 | | 3 | | 5 | | 6 | | 9 |
| | | | | | | | | | | |
+-----+ +-----+ +-----+ +-----+ +-----+ +-----+
1 2 3 5 6 9
+---+---+ +---+---+ +---+---+ +---+---+ +---+---+
| | | | | | | | | | | | | | |
| 1 | 2 | | 1 | 6 | | 2 | 0 | | 2 | 1 | | 3 | 0 |
| | | | | | | | | | | | | | |
+-------+ +-------+ +---+---+ +---+---+ +---+---+
12 12 20 21 30
Each of the eight months representable of the month cube may be combined with each of the 11 numbers of the day cube giving 88 possible representable dates. With the day cube's "M", "N", "O" and "S" and the month cube's "3", "4" and "5", an additional 8 dates (the 3rd and 5th for March and September being already represented with month cube then day cube) are representable, for a combined total of
96 possible representable dates.
Note: There may be variations to some of the months and numbers for dates represented, but I believe 96 may be the maximum unless one can figure how to stylize the letters/numbers to increase the possibilities OR by altering how the dates may be presented.
------------------------------------------------------------
The following is an attempt to show how the letters/numbers might be stylized:
xxxxxxx x x
x x x x
xxxxxxx x x x 3 / M (3 rotated)
x x x x
xxxxxxx x x x
xxxxxxx x x x x
x x x x
xxxxxxx x x x 2 / N (2 rotated)
x x x x
xxxxxxx x x x x
xxxxxxxxx x x
x x x J / 4 (J rotated)
x xxxxxxx
xxxxx x
x
xxx xxxxxxx
x x x
x x xxxxxxx O / 0 (zero) & S / 5
x x x
xxx xxxxxxx
xxxx xxxxxxxx
x x x x
x x x x A / D (A rotated)
xxxxxxxxxx x x
x x x x
x x xxxxxxxx
Edited on July 3, 2010, 6:02 pm
|
Posted by Dej Mar
on 2010-07-03 14:22:11 |