Let ABCDE be a convex pentagon such that the
triangles ABC, ACD, and ADE are similar.
The diagonals BD and CE intersect in point P.

Prove that the ray AP bisects side CD.

(In reply to re(2): Question? by broll)

 

Right off I see Angle BAC = Angle ACD.

But, for similarity Angle BAC must equal Angle CAD.

Posted by Bractals on 2010-10-18 14:27:16