Let ABCDE be a convex pentagon such that the
triangles ABC, ACD, and ADE are similar.
The diagonals BD and CE intersect in point P.

Prove that the ray AP bisects side CD.

(In reply to re(6): Question? by ed bottemiller)

I have now worked this out. The figure has to be drawn so that angles:

• ABC = ACD = ADE
• BAC = CAD = DAE
• ACB = ADC = AED

The puzzle then 'works'.

No doublt Bractals will be swift to pick up any typos in the above!

Posted by broll on 2010-10-18 19:32:37