They are congruent.
Let's construct triangle ABC.
1) Draw point and call it B.
2) Draw two line segments that end at point B and form an angle = /DEF.
3) Pick point A on one of the segments, such that |AB| = |DE|.
4) Using a compass, find point C on the other segment such that |AC| = |DF|. Because /DEF > 90°, |DF| is the longest side of the triangle, so there is only one possibility for C on the other segment. And because the choice of C is forced, the triangles are necessarily congruent.