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Seven come eleven (Posted on 2010-12-11) Difficulty: 4 of 5
  A positive integer N fulfills the following demands:.
N is a 7 digit number.
N's digits can be arranged as seven distinct members of an arithmetic progression(either ascending or descending) .

N is a multiple of 11.

How many positive integers like N exist?
Evaluate the lowest and the highest N.
BONUS : How about 8 digits? Nine? All ten?
  Rem: It is D4 for fully explained and errorless P&P result,might be significantly lower for software solution.    

See The Solution Submitted by Ady TZIDON    
Rating: 4.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Hints/Tips re(3): for 10 digits ?????? remark | Comment 8 of 13 |
(In reply to re(2): for 10 digits ?????? by Charlie)

The Lowest and Highest can be worked out "manually" i.e. P&P .

This is true for any amount of distinct digits.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 


  Posted by Ady TZIDON on 2010-12-11 16:45:36
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