2011=670*3+1+2+4+8-9-5

We have just welcomed the New Year, using all 10 digits and 4 basic arithmetic signs(+, -, /, and *).

Try to get 2011 with ALL 10 digits, significantly fewer signs and no brackets.

Hint: My solution uses 10 distinct digits and 3 signs only, but maybe a better solution exists.

(In reply to re(5): best I can do -- the program for the solutions by Charlie)

Ch,

Did you look for "one sign only " solution,

like abcde-ghijk=2011  ?

It does not look feasible, but I did not prove it cannot exist.

Your program confirms existence of 2-sign solution in abundance, so maybe that's the best we all can do.

Posted by Ady TZIDON on 2011-01-01 18:45:38