Randomly draw three from a standard set of 28 Double Six Dominoes.

What is the probability they can be arranged in a triangle with each end touching another end with an equal number of spots?
For example: [1|3][3|0][0|1] can form such a triangle.
(Note: this triangle is not a legal configuration in an actual game of dominoes.)

Randomly draw four dominoes instead.
What is the probability of being able to form a square in the same fashion?

How about 5? 6? 27? 26?

There doesn't seem to be a general formula. Is there?

25 randomly drawn can form a 25-gon only if the undrawn three are all doubles, or if they form a triangle.

Posted by Steve Herman on 2011-03-15 14:57:50