Which regular polygons can be dissected into isosceles triangles by non-intersecting diagonals?
(In reply to
re: Not sure if this is what you want - A rewrite. by Jer)
I read "non-intersecting" as within the defined area.
Interesting how we can misinterpret, or even misrepresent terminology; we carelessly refer, for instance, to the 4 diagonals of a square when in fact they are axes of symmetry.
Ok! For starters, these seem right:
Pentagon - 5; one tall and thin flanked by two on the perimeter
Hexagon - 3 but with an enclosed equilateral!!! Not a solution.
Octagon - 6; 4 around the perimeter to leave a square divided corner to corner.
Decagon - 8; 5 around the perimeter to create a pentagon which is divided as above.
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Posted by brianjn
on 2012-01-21 02:16:56 |