Let ABC be a triangle with points D and E lying on
lines AC and AB respectively such that D and E are
on the same side of line BC and |BE| = |CD| > 0. Let F be the intersection of rays BD and CE.
What is the locus of the intersections F?
Prove it.
(In reply to
re: Initital exploration by Bractals)
You know what? I never use the locus command.
(It may even be that I've never used it!)
I just created point D, a circle centered at C containing D and the other intersection (D'). Then I translated this circle to B and created two more intersections(E and E'). Then I drew both possible sets of BD and CE, traced their intersections (F and F'), and animated D.
Once this trace looked like a line I just connected F and F'.
I tried an algebraic solution earlier this afternoon but the terms went all 4th power on me.
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Posted by Jer
on 2012-03-10 00:34:58 |