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Internal & External (Posted on 2003-05-09) Difficulty: 2 of 5
Side-tracked from a slightly related problem, I derived this general set of attributes:

{8, 12n, 6n^2, n^2, n}.

The first 5 situations of this generalisation are:

[8, 0, 0, 0, 0],
[8, 12, 6, 1, 1],
[8, 24, 24, 4, 2],
[8, 36, 54, 9, 3],
[8, 48, 96, 16, 4].

What does this set of attributes describe?

(Attributes #1 & #4 may provide clues. Also, take note of the Title.)

See The Solution Submitted by brianjn    
Rating: 3.1667 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Hints/Tips re: First guess.... | Comment 6 of 16 |
(In reply to First guess.... by Brian Smith)

Hey! This is a fine interpretation of the data given and certainly fits the generalisation, however this does not describe my scenario.

Yes, 8 are for vertices. 'n' describes the 'order' of the cube to which these attributes apply. In terms of edge length, 'n' is actually n+2 units.
  Posted by Brian Nowell on 2003-05-09 21:13:00

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