All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Logic
Mutually friendly 3 (Posted on 2012-08-05) Difficulty: 4 of 5
Prove that if any two people are either friends or strangers, then any group of 18 people contains either 4 mutual friends or 4 mutual strangers.

See The Solution Submitted by Math Man    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(4): No Subject | Comment 8 of 11 |
(In reply to re(3): No Subject by Chris, PhD)

I've been on that same drawing board for quite a length of time now, as you can see with the proof I came up with for a total of 20.  Because of what was pointed out about "Ramsey's Theorem", I can somewhat buy into the idea that it can indeed be shown to be true among a group of 18 -- but I'm at a complete loss as to why this is the case...
  Posted by Caleb on 2012-08-07 12:33:13

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information