What is the 73rd digit from the end of a2?
list 10 A=(10^2012-1)//9 20 B=modpow(A,2,10^73) 30 print B\10^72OKrun 0
showing zero as the answer.
The last 74 digits are:
?modpow(A,2,10^74)
20987654320987654320987654320987654320987654320987654320987654320987654321
blackjack
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flooble's webmaster puzzle
computer solution
