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Fun sequence (
Posted on 2013-03-01
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1, 3, 10, 33, 109, ?...
No Solution Yet
Submitted by
Math Man
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?... SPOILER
Comment 1 of 1
a(6)=
360
=3*109+33
a(n)=3*a(n-1)+(n-2)
The solution can be obtained either:
a) by assuming recurrence like a(n)=A*a(n-1)+B*a(n-2)+C
& evaluating A,B,C from the given members of the "fun (?)" seq.
or
b) check-in @ OEIS
Posted by
Ady TZIDON
on 2013-03-01 17:52:44
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