(1) Take a 3 digit number whose first digit is greater than its last.

(2) Reverse the digits of (1) to create a smaller number.

(3) Subtract the number in (2) from (1) (Add a leading zero if this number is not 3 digits)

(4) Reverse the digits of (3)

(5) Add the numbers from steps (3) and (4)

What is the result, and why?

It's always zero.  Let the first 3 digit number be 100*a+10*b+c.  Then go through transformations.  It always comes out zero.

Posted by Kenny M on 2013-04-09 19:31:01