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Coin Toss (Posted on 2013-06-13) Difficulty: 3 of 5
Two persons engage in a game of chance. The game is to nominate a sequence of three consecutive coin tosses [H or T].

Player one firstly nominates a sequence and then player two makes a nomination. The game finishes when the last three tosses match either one of the players' nominations.

How can player two be assured of winning most of the time?

Given the choices that can be made by player one, what are the odds of player two winning?

Oh, it doesn't matter who tosses the coin.

See The Solution Submitted by brianjn    
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Some Thoughts A thought | Comment 2 of 4 |
I haven't given it much thought, but, as player two,  I'd follow this strategy:
If player 1 tosses XYZ (3 letters used for clarity)
I'd use YZA, which would give me 50%, by always nominating the last two choices of 1 as my first two choices.

I'll leave it to bigger brains to figure out if this is a good strategy and what odds are involved.

Edited on June 13, 2013, 7:03 pm
  Posted by Hugo on 2013-06-13 18:59:04

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