A selection of eight cards is dealt with every second card being returned to the bottom of the pack. Thus the top card goes to the table, card two goes to the bottom of the pack, card three goes to the table, card four to the bottom of the pack, and so on. This procedure continues until all cards are dealt.
The order in which the cards appear on the table is:
A K A K A K A K
How were the cards originally stacked?
(In reply to
What if...SPOILER by Ady TZIDON)
If the cards in the original pack are numbered 1 through 8, we can see where they end up:
Table Pack
12345678
1 3456782
13 567824
135 78246
1357 2468
13572 684
135726 48
1357264 8
13572648
So whatever card you want to come out first should start off first; whatever card you want second should start out third, etc.
So to answer Ady's question:
AcKcAdKdAhKhAsKs
1 3 5 7 2 6 4 8
the original sequence traces back those numbers:
AcAhKcAsAdKhKdKs
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Posted by Charlie
on 2013-06-20 11:16:51 |
re: What if...SPOILER -- general solution and Ady's question
