Find the lowest possible value of the function
f(x) = x²⁰⁰⁸ - 2x²⁰⁰⁷ + 3x²⁰⁰⁶ - ... + 2007x² - 2008x + 2009
for any real numbers x.

sigma n=1 to n=1004 ((2n-1)*x^(2009-(2n-1))-(2n)*x^(2009-(2n))+2009/1004), produces the requested expression.

Trying small values seems to confirm a minimum of 1005 at x=1

Posted by broll on 2013-06-27 01:14:40